Match List-I with List-II. Choose the correct | vedclass

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Question

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \right

Vedclass · Accepted Answer

$A-IV, B-III, C-I, D-II$

Vedclass · Answer

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \rightarrow$ Reimer-Tiemann reaction: Phenol reacts with $CHCl_3$ and $NaOH$ followed by $HCl$ to form salicylaldehyde. Matches with $III$.$C \rightarrow$ Oxidation of phenol: Phenol is oxidized by $Na_2Cr_2O_7$ and $H_2SO_4$ to $p$-benzoquinone. Matches with $I$.$D \rightarrow$ Williamson ether synthesis: Phenol reacts with $NaOH$ to form sodium phenoxide,which then reacts with $CH_3Cl$ to form anisole $(PhOCH_3)$. Matches with $II$.Therefore,the correct matching is $A-IV, B-III, C-I, D-II$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. Cumene $+ O_2$	$i$. Phenol
$B$. Benzene sulphonic acid $\xrightarrow{NaOH, H^+}$	$ii$. $2$-Methylbutan-$1$-ol
$C$. Chlorobenzene $+ NaOH \xrightarrow{623 \ K, 300 \ atm}$	$iii$. Cumene hydroperoxide
$D$. $2$-Methylbutanal $\xrightarrow{NaBH_4}$	$iv$. Sodium phenoxide

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:

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